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HL Paper 2

Magnesium is a group 2 metal which exists as a number of isotopes and forms many compounds.

Magnesium ions produce no emission or absorption lines in the visible region of the electromagnetic spectrum. Suggest why most magnesium compounds tested in a school laboratory show traces of yellow in the flame.

[1]
c.

(i) Explain the convergence of lines in a hydrogen emission spectrum.

(ii) State what can be determined from the frequency of the convergence limit.

[2]
d.

Magnesium chloride can be electrolysed.

(i) Deduce the half-equations for the reactions at each electrode when molten magnesium chloride is electrolysed, showing the state symbols of the products. The melting points of magnesium and magnesium chloride are 922K and 987K respectively.

(ii) Identify the type of reaction occurring at the cathode (negative electrode).

(iii) State the products when a very dilute aqueous solution of magnesium chloride is electrolysed.

[5]
i.

Standard electrode potentials are measured relative to the standard hydrogen electrode. Describe a standard hydrogen electrode.

[2]
j.

A magnesium half-cell, Mg(s)/Mg2+(aq), can be connected to a copper half-cell, Cu(s)/Cu2+(aq).

(i) Formulate an equation for the spontaneous reaction that occurs when the circuit is completed.

(ii) Determine the standard cell potential, in V, for the cell. Refer to section 24 of the data booklet.

(iii) Predict, giving a reason, the change in cell potential when the concentration of copper ions increases.

[4]
k.

Markscheme

contamination with sodium/other «compounds»

c.

i
energy levels are closer together at high energy / high frequency / short wavelength

 

ii
ionisation energy

d.

i)

Anode (positive electrode):

2Cl → Cl2 (g) + 2e

Cathode (negative electrode):

Mg2+ + 2e → Mg (l)

Penalize missing/incorrect state symbols at Cl2 and Mg once only.

Award [1 max] if equations are at wrong electrodes.

Accept Mg (g).

 

ii)

reduction

 

iii)

Anode (positive electrode):
oxygen/O2
OR
hydogen ion/proton/H+ AND oxygen/O2
Cathode (negative electrode):
hydrogen/H2
OR
hydroxide «ion»/OH AND hydrogen/H2

Award [1 max] if correct products given at wrong electrodes.

 

i.

Any two of:

«inert» Pt electrode
OR
platinum black conductor

1 mol dm–3 H(aq)

H2 (g) at 100 kPa

Accept 1 atm H2 (g).
Accept 1 bar H2 (g)
Accept a labelled diagram.
Ignore temperature if it is specified.

j.

i

Mg(s) + Cu2+ (aq) → Mg2+ (aq) + Cu(s)

 

ii

«+0.34V – (–2.37V) = +»2.71 «V»

 

iii

cell potential increases

reaction «in Q4(k)(i)» moves to the right
OR
potential of the copper half-cell increases/becomes more positive

Accept correct answers based on the Nernst equation

k.

Examiners report

[N/A]
c.
[N/A]
d.
[N/A]
i.
[N/A]
j.
[N/A]
k.



Chlorine undergoes many reactions.

2.67g of manganese(IV) oxide was added to 200.0cm3 of 2.00moldm-3 HCl.

MnO2(s)+4HCl(aq)Cl2(g)+2H2O(l)+MnCl2(aq)

Chlorine gas reacts with water to produce hypochlorous acid and hydrochloric acid.

Cl2(g)+H2O(l)HClO(aq)+HCl(aq)

CCl2F2 is a common chlorofluorocarbon, CFC.

State the full electron configuration of the chlorine atom.

[1]
a(i).

State, giving a reason, whether the chlorine atom or the chloride ion has a larger radius.

[1]
a(ii).

Outline why the chlorine atom has a smaller atomic radius than the sulfur atom.

[2]
a(iii).

The mass spectrum of chlorine is shown.

NIST Mass Spectrometry Data Center Collection © 2014 copyright by the U.S. Secretary of Commerce on behalf of the United States of America. All rights reserved.


Outline the reason for the two peaks at m/z=35 and 37.

[1]
a(iv).

Explain the presence and relative abundance of the peak at m/z=74.

[2]
a(v).

Calculate the amount, in mol, of manganese(IV) oxide added.

[1]
b(i).

Determine the limiting reactant, showing your calculations.

[2]
b(ii).

Determine the excess amount, in mol, of the other reactant.

[1]
b(iii).

Calculate the volume of chlorine, in dm3, produced if the reaction is conducted at standard temperature and pressure (STP). Use section 2 of the data booklet.

[1]
b(iv).

State the oxidation state of manganese in MnO2 and MnCl2.

[2]
b(v).

Deduce, referring to oxidation states, whether MnO2 is an oxidizing or reducing agent.

[1]
b(vi).

Hypochlorous acid is considered a weak acid. Outline what is meant by the term weak acid.

 

[1]
c(i).

State the formula of the conjugate base of hypochlorous acid.

[1]
c(ii).

Calculate the concentration of H+(aq) in a HClOaq solution with a pH=3.61.

[1]
c(iii).

State the type of reaction occurring when ethane reacts with chlorine to produce chloroethane.

[1]
d(i).

Predict, giving a reason, whether ethane or chloroethane is more reactive.

[1]
d(ii).

Explain the mechanism of the reaction between chloroethane and aqueous sodium hydroxide, NaOH(aq), using curly arrows to represent the movement of electron pairs.

[3]
d(iii).

Ethoxyethane (diethyl ether) can be used as a solvent for this conversion.
Draw the structural formula of ethoxyethane

[1]
d(iv).

Deduce the number of signals and chemical shifts with splitting patterns in the 1H NMR spectrum of ethoxyethane. Use section 27 of the data booklet.

[3]
d(v).

Calculate the percentage by mass of chlorine in CCl2F2.

[2]
e(i).

Comment on how international cooperation has contributed to the lowering of CFC emissions responsible for ozone depletion.

[1]
e(ii).

CFCs produce chlorine radicals. Write two successive propagation steps to show how chlorine radicals catalyse the depletion of ozone.

[2]
e(iii).

Markscheme

1s22s22p63s23p5 ✔


Do not accept condensed electron configuration.

a(i).

Cl- AND more «electron–electron» repulsion ✔


Accept Cl- AND has an extra electron.

a(ii).

Cl has a greater nuclear charge/number of protons/Zeff «causing a stronger pull on the outer electrons» ✔

same number of shells
OR
same «outer» energy level
OR
similar shielding ✔

a(iii).

«two major» isotopes «of atomic mass 35 and 37» ✔

a(iv).

«diatomic» molecule composed of «two» chlorine-37 atoms ✔

chlorine-37 is the least abundant «isotope»
OR
low probability of two Cl37 «isotopes» occurring in a molecule ✔

a(v).

«2.67g86.94gmol-1=»0.0307«mol» ✔

b(i).

«nHCl=2.00moldm-3×0.2000dm3»=0.400mol 

«0.4004=»0.100mol AND MnO2 is the limiting reactant ✔


Accept other valid methods of determining the limiting reactant in M2.

b(ii).

«0.0307mol×4=0.123mol»

«0.400mol0.123mol=»0.277«mol» ✔

b(iii).

«0.0307mol×22.7dm3mol1=»0.697«dm3» ✔


Accept methods employing pV=nRT
.

b(iv).

MnO2: +4 ✔

MnCl2: +2 ✔

b(v).

oxidizing agent AND oxidation state of Mn changes from +4 to +2/decreases ✔

b(vi).

partially dissociates/ionizes «in water» ✔

c(i).

ClO- ✔

c(ii).

«[H+]=103.61=»2.5×104«moldm3» ✔

c(iii).

«free radical» substitution/SR


Do not accept electrophilic or nucleophilic substitution.

d(i).

chloroethane AND C–Cl bond is weaker/324kJmol1 than C–H bond/414kJmol1
OR
chloroethane AND contains a polar bond ✔


Accept “chloroethane AND polar”.

d(ii).

curly arrow going from lone pair/negative charge on O in OH to C

curly arrow showing Cl leaving ✔

representation of transition state showing negative charge, square brackets and partial bonds ✔

 

Accept OH- with or without the lone pair.

Do not accept curly arrows originating on H in OH-.

Accept curly arrows in the transition state.

Do not penalize if HO and Cl are not at 180°.

Do not award M3 if OH-C bond is represented. 

d(iii).

 / CH3CH2OCH2CH3


Accept (CH3CH2)2O.

d(iv).

2 «signals» ✔

0.9−1.0 AND triplet ✔

3.3−3.7 AND quartet ✔

Accept any values in the ranges.

Award [1] for two correct chemical shifts or two correct splitting patterns.

d(v).

«M(CCl2F2) =»120.91«gmol1»  ✔

2×35.45gmol-1120.91gmol-1×100%=»58.64«%» ✔


Award [2] for correct final answer.

e(i).

Any of:

research «collaboration» for alternative technologies «to replace CFC
OR
technologies «developed»/data could be shared
OR
political pressure/Montreal Protocol/governments passing legislations ✔

 

Do not accept just “collaboration”.

Do not accept any reference to CFC as greenhouse gas or product of fossil fuel combustion.

Accept reference to specific measures, such as agreement on banning use/manufacture of CFCs.

e(ii).

O3+Cl·O2+ClO· ✔

ClO·+O·O2+Cl·
OR
ClO·+O3Cl·+2O2 ✔

Penalize missing/incorrect radical dot (∙) once only.

e(iii).

Examiners report

Well answered question with 90% of candidates correctly identifying the complete electron configuration for chlorine.

a(i).

Most candidates could correctly explain the relative sizes of chlorine atom and chloride ion.

a(ii).

Fairly well answered though some candidates missed M2 for not recognizing the same number of shells affected.

a(iii).

More than 80% could identify that the two peaks in the MS of chlorine are due to different isotopes.

a(iv).

Not well answered. Some candidates were able to identify m/z 74 being due to the m/z of two Cl-37 atoms, however fewer candidates were able to explain the relative abundance of the isotope.

a(v).

Stoichiometric calculations were generally well done and over 90% could calculate mol from a given mass.

b(i).

90% of candidates earned full marks on this 2-mark question involving finding a limiting reactant.

b(ii).

Surprisingly, quite a number of candidates struggled with the quantity of excess reactant despite correctly identifying limiting reactant previously.

b(iii).

Most candidates could find the volume of gas produced in a reaction under standard conditions.

b(iv).

More than 90% could identify the oxidation number of manganese in both MnO2 and MnCl2.

b(v).

Most candidates stated that MnO2 is an oxidizing agent in the reaction but many did not get the mark because there was no reference to oxidation states.

b(vi).

Another well answered 1-mark question where candidates correctly identified a weak acid as an acid which partially dissociates in water. 

c(i).

Roughly ⅓ of the candidates failed to identify the conjugate base, perhaps distracted by the fact it was not contained in the equation given.

c(ii).

Vast majority of candidates could calculate the concentration of H+ (aq) in a HClO (aq) solution with a pH =3.61.

c(iii).

Many identified the reaction of chlorine with ethane as free-radical substitution, or just substitution, with some erroneously stating nucleophilic or electrophilic substitution.

d(i).

The underlying reasons for the relative reactivity of ethane and chloroethane were not very well known with a few giving erroneous reasons and some stating ethane more reactive.

d(ii).

Few earned full marks for the curly arrow mechanism of the reaction between sodium hydroxide and chloroethane. Mistakes being careless curly arrow drawing, inappropriate –OH notation, curly arrows from the hydrogen or from the carbon to the C–Cl bond, or a method that missed the transition state.

d(iii).

Approximately 60% could draw ethoxyethane however many demonstrated little knowledge of structure of an ether molecule.

d(iv).

A poorly answered question with some getting full marks on this 1HNMR spectrum of ethoxyethane question. Very few could identify all 3 of number of signals, chemical shift, and splitting pattern.

d(v).

Another good example of candidates being well rehearsed in calculations with 90% earning 2/2 on this question of calculation percentage by mass composition. 

e(i).

Somewhat disappointing answers on this question about how international cooperation has contributed to the lowering of CFC emissions. Many gave vague answers and some referred to carbon emissions and global warming.

e(ii).

Few could construct the propagation equations showing how CFCs affect ozone, and many lost marks by failing to identify ClO· as a radical.

e(iii).



Nickel catalyses the conversion of propanone to propan-2-ol.

Outline how a catalyst increases the rate of reaction.

[1]
a.

Explain why an increase in temperature increases the rate of reaction.

[2]
b.

Discuss, referring to intermolecular forces present, the relative volatility of propanone and propan-2-ol.

[3]
c.

The diagram shows an unlabelled voltaic cell for the reaction

Pb2+(aq)+Ni(s)Ni2+(aq)+Pb(s)

Label the diagram with the species in the equation.

[1]
d(i).

Calculate the standard cell potential, in V, for the cell at 298K. Use section 24 of the data booklet

[1]
d(ii).

Calculate the standard free energy change, G, in kJ, for the cell using sections 1 and 2 of the data booklet.

[1]
d(iii).

Suggest a metal that could replace nickel in a new half-cell and reverse the electron flow. Use section 25 of the data booklet.

[1]
d(iv).

Describe the bonding in metals.

[2]
d(v).

Nickel alloys are used in aircraft gas turbines. Suggest a physical property altered by the addition of another metal to nickel.

[1]
d(vi).

Markscheme

provides an alternative pathway/mechanism AND lower Ea ✔

Accept description of how catalyst lowers Ea (e.g. “reactants adsorb on surface «of catalyst»”, “reactant bonds weaken «when adsorbed»”).

a.

more/greater proportion of molecules with E E

greater frequency/probability/chance of collisions «between the molecules»
OR
more collision per unit of time/second ✔

b.

hydrogen bonding/bonds «and dipole–dipole and London/dispersion forces are present in» propan-2-ol ✔

dipole–dipole «and London/dispersion are present in» propanone ✔

propan-2-ol less volatile AND hydrogen bonding/bonds stronger «than dipole–dipole »
OR
propan-2-ol less volatile AND «sum of all» intermolecular forces stronger ✔

c.

d(i).

«0.13V(0.26V)=+»0.13«V» ✔

d(ii).

«ΔGΘ=nFEΘ=2×96500×0.131000=»25«kJ» ✔

d(iii).

Bi/Cu/Ag/Pd/Hg/Pt/Au  ✔

Accept Sb OR As.

d(iv).

electrostatic attraction ✔

between «a lattice of» metal/positive ions/cations AND «a sea of» delocalized electrons ✔

Accept “mobile/free electrons”.

d(v).

Any of:

malleability/hardness
OR
«tensile» strength/ductility
OR
density
OR
thermal/electrical conductivity
OR
melting point
OR
thermal expansion ✔

Do not accept corrosion/reactivity or any chemical property.

Accept other specific physical properties.

d(vi).

Examiners report

Although fairly well done some candidates did not mention that providing an alternate pathway to the reaction was how the activation energy was lowered and hence did not gain the mark.

a.

Almost all candidates earned at least 1 mark for the effect of temperature on rate. Some missed increase in collision frequency, others the idea that more particles reached the required activation energy.

b.

The average mark was 1.9/3. Almost all candidates could recognize hydrogen bonding in alcohol but many missed the dipole-dipole attraction in propanone. There was also some confusion on the term volatility, with some thinking stronger IMF meant higher volatility.

c.

A surprising number of No Response for a question where candidates simply had to label a diagram with the species in the equation. Some candidates had the idea but did not use the species for electrolytic cell, e.g., Pb(SO4) instead of Pb2+(aq).

d(i).

80% of candidates could correctly calculate a cell potential by using a reduction table and a balanced redox reaction. 

d(ii).

This was similar to 2f(ii) where many could apply the formula for Gibbs free energy change, ΔGө, correctly however some did not get the units correct.

d(iii).

80% could correctly pick a metal to reverse the electron flow, however some candidates thought a more reactive, rather than a less reactive metal than nickel would reverse the electron flow.

d(iv).

Most candidates were aware that metallic bonding involved a "sea of electrons", but were unsure about surrounding what and could not identify that it was electrostatic attraction holding the metal together.

d(v).

Almost all candidates could correctly identify a physical property of a metal which might be altered when alloying.

d(vi).